120131310210120 has 1024 divisors, whose sum is σ = 447228739584000. Its totient is φ = 28439656243200.

The previous prime is 120131310210101. The next prime is 120131310210167. The reversal of 120131310210120 is 21012013131021.

120131310210120 is a `hidden beast` number, since 1 + 2 + 0 + 131 + 310 + 210 + 12 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 120131310210093 and 120131310210102.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 37932208777 + ... + 37932211943.

It is an arithmetic number, because the mean of its divisors is an integer number (436746816000).

Almost surely, 2^{120131310210120} is an apocalyptic number.

120131310210120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120131310210120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (223614369792000).

120131310210120 is an abundant number, since it is smaller than the sum of its proper divisors (327097429373880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131310210120 is a wasteful number, since it uses less digits than its factorization.

120131310210120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3691 (or 3681 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 120131310210120 its reverse (21012013131021), we get a palindrome (141143323341141).

The spelling of 120131310210120 in words is "one hundred twenty trillion, one hundred thirty-one billion, three hundred ten million, two hundred ten thousand, one hundred twenty".