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1201313303222 = 2600656651611
BaseRepresentation
bin10001011110110011110…
…110100100101010110110
311020211210120220211022112
4101132303312210222312
5124140242201200342
62315513053131022
7152535443411264
oct21366366445266
94224716824275
101201313303222
1142352405025a
121749a5489a72
138938b6ccbc6
1442202b0d434
15213b0157682
hex117b3da4ab6

1201313303222 has 4 divisors (see below), whose sum is σ = 1801969954836. Its totient is φ = 600656651610.

The previous prime is 1201313303219. The next prime is 1201313303269. The reversal of 1201313303222 is 2223033131021.

It is a semiprime because it is the product of two primes.

It is a super-4 number, since 4×12013133032224 (a number of 49 digits) contains 4444 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300328325804 + ... + 300328325807.

It is an arithmetic number, because the mean of its divisors is an integer number (450492488709).

Almost surely, 21201313303222 is an apocalyptic number.

1201313303222 is a deficient number, since it is larger than the sum of its proper divisors (600656651614).

1201313303222 is an equidigital number, since it uses as much as digits as its factorization.

1201313303222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600656651613.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1201313303222 its reverse (2223033131021), we get a palindrome (3424346434243).

The spelling of 1201313303222 in words is "one trillion, two hundred one billion, three hundred thirteen million, three hundred three thousand, two hundred twenty-two".

Divisors: 1 2 600656651611 1201313303222