Base | Representation |
---|---|
bin | 10001011110110011110… |
… | …110100100101010110110 |
3 | 11020211210120220211022112 |
4 | 101132303312210222312 |
5 | 124140242201200342 |
6 | 2315513053131022 |
7 | 152535443411264 |
oct | 21366366445266 |
9 | 4224716824275 |
10 | 1201313303222 |
11 | 42352405025a |
12 | 1749a5489a72 |
13 | 8938b6ccbc6 |
14 | 42202b0d434 |
15 | 213b0157682 |
hex | 117b3da4ab6 |
1201313303222 has 4 divisors (see below), whose sum is σ = 1801969954836. Its totient is φ = 600656651610.
The previous prime is 1201313303219. The next prime is 1201313303269. The reversal of 1201313303222 is 2223033131021.
It is a semiprime because it is the product of two primes.
It is a super-4 number, since 4×12013133032224 (a number of 49 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300328325804 + ... + 300328325807.
It is an arithmetic number, because the mean of its divisors is an integer number (450492488709).
Almost surely, 21201313303222 is an apocalyptic number.
1201313303222 is a deficient number, since it is larger than the sum of its proper divisors (600656651614).
1201313303222 is an equidigital number, since it uses as much as digits as its factorization.
1201313303222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 600656651613.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1201313303222 its reverse (2223033131021), we get a palindrome (3424346434243).
The spelling of 1201313303222 in words is "one trillion, two hundred one billion, three hundred thirteen million, three hundred three thousand, two hundred twenty-two".
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