Base | Representation |
---|---|
bin | 11011010100001001000111… |
… | …110101100111001001000100 |
3 | 120202100110020122021112111120 |
4 | 123110021013311213021010 |
5 | 111221213142232133122 |
6 | 1103255342155033540 |
7 | 34206132041065560 |
oct | 3324110765471104 |
9 | 522313218245446 |
10 | 120131440505412 |
11 | 35306504388386 |
12 | 1158234043b8b0 |
13 | 520546689286b |
14 | 219456d9926a0 |
15 | dd4d63bb075c |
hex | 6d4247d67244 |
120131440505412 has 96 divisors (see below), whose sum is σ = 322128010364160. Its totient is φ = 34132831004160.
The previous prime is 120131440505299. The next prime is 120131440505473. The reversal of 120131440505412 is 214505044131021.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 986329014 + ... + 986450802.
It is an arithmetic number, because the mean of its divisors is an integer number (3355500107960).
Almost surely, 2120131440505412 is an apocalyptic number.
120131440505412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
120131440505412 is an abundant number, since it is smaller than the sum of its proper divisors (201996569858748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120131440505412 is a wasteful number, since it uses less digits than its factorization.
120131440505412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186861 (or 186859 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 120131440505412 its reverse (214505044131021), we get a palindrome (334636484636433).
The spelling of 120131440505412 in words is "one hundred twenty trillion, one hundred thirty-one billion, four hundred forty million, five hundred five thousand, four hundred twelve".
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