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120132002281 is a prime number
BaseRepresentation
bin110111111100001101…
…1001110000111101001
3102111002012120000120211
41233320123032013221
53432012243033111
6131104325421121
711451661112464
oct1577033160751
9374065500524
10120132002281
1146a47424415
121b347b6a7a1
13b436654325
145b58aa82db
1531d187c521
hex1bf86ce1e9

120132002281 has 2 divisors, whose sum is σ = 120132002282. Its totient is φ = 120132002280.

The previous prime is 120132002233. The next prime is 120132002321. The reversal of 120132002281 is 182200231021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75141774400 + 44990227881 = 274120^2 + 212109^2 .

It is an emirp because it is prime and its reverse (182200231021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120132002281 is a prime.

It is a super-2 number, since 2×1201320022812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120132002381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066001140 + 60066001141.

It is an arithmetic number, because the mean of its divisors is an integer number (60066001141).

Almost surely, 2120132002281 is an apocalyptic number.

It is an amenable number.

120132002281 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132002281 is an equidigital number, since it uses as much as digits as its factorization.

120132002281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

The spelling of 120132002281 in words is "one hundred twenty billion, one hundred thirty-two million, two thousand, two hundred eighty-one".