Base | Representation |
---|---|
bin | 11011010100001001101001… |
… | …111011010101100000101100 |
3 | 120202100111201111110101110201 |
4 | 123110021221323111200230 |
5 | 111221220330140301104 |
6 | 1103255515025243244 |
7 | 34206152154300361 |
oct | 3324115173254054 |
9 | 522314644411421 |
10 | 120132012431404 |
11 | 35306778200896 |
12 | 1158247ba93524 |
13 | 520552820bccc |
14 | 21945c590c468 |
15 | dd4d98ed50a4 |
hex | 6d4269ed582c |
120132012431404 has 48 divisors (see below), whose sum is σ = 210986052480000. Its totient is φ = 59850547193216.
The previous prime is 120132012431383. The next prime is 120132012431441. The reversal of 120132012431404 is 404134210231021.
It is a happy number.
It is a super-2 number, since 2×1201320124314042 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20351007117 + ... + 20351013019.
It is an arithmetic number, because the mean of its divisors is an integer number (4395542760000).
Almost surely, 2120132012431404 is an apocalyptic number.
It is an amenable number.
120132012431404 is a deficient number, since it is larger than the sum of its proper divisors (90854040048596).
120132012431404 is a wasteful number, since it uses less digits than its factorization.
120132012431404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14142 (or 14140 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 120132012431404 its reverse (404134210231021), we get a palindrome (524266222662425).
The spelling of 120132012431404 in words is "one hundred twenty trillion, one hundred thirty-two billion, twelve million, four hundred thirty-one thousand, four hundred four".
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