120132017 has 2 divisors, whose sum is σ = 120132018. Its totient is φ = 120132016.

The previous prime is 120131989. The next prime is 120132029. The reversal of 120132017 is 710231021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107143201 + 12988816 = 10351^2 + 3604^2 .

It is a cyclic number.

It is not a de Polignac number, because 120132017 - 2¹² = 120127921 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120131986 and 120132004.

It is not a weakly prime, because it can be changed into another prime (120132097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066008 + 60066009.

It is an arithmetic number, because the mean of its divisors is an integer number (60066009).

Almost surely, 2^120132017 is an apocalyptic number.

It is an amenable number.

120132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132017 is an equidigital number, since it uses as much as digits as its factorization.

120132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 120132017 is about 10960.4752177996. The cubic root of 120132017 is about 493.4232274199.

Adding to 120132017 its reverse (710231021), we get a palindrome (830363038).

The spelling of 120132017 in words is "one hundred twenty million, one hundred thirty-two thousand, seventeen".