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120132021031000 = 23531119683841573
BaseRepresentation
bin11011010100001001101010…
…011100001001000001011000
3120202100111202002122021220021
4123110021222130021001120
5111221220334340443000
61103255515533440224
734206152320345156
oct3324115234110130
9522314662567807
10120132021031000
11353067820448a0
1211582482940074
135205529c30324
1421945c6b0a3d6
15dd4d99b3311a
hex6d426a709058

120132021031000 has 256 divisors, whose sum is σ = 323277523545600. Its totient is φ = 41324551488000.

The previous prime is 120132021030947. The next prime is 120132021031027. The reversal of 120132021031000 is 130120231021.

It is a super-2 number, since 2×1201320210310002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 142326214 + ... + 143167786.

It is an arithmetic number, because the mean of its divisors is an integer number (1262802826350).

Almost surely, 2120132021031000 is an apocalyptic number.

120132021031000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120132021031000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161638761772800).

120132021031000 is an abundant number, since it is smaller than the sum of its proper divisors (203145502514600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120132021031000 is a wasteful number, since it uses less digits than its factorization.

120132021031000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 842307 (or 842293 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 120132021031000 its reverse (130120231021), we get a palindrome (120262141262021).

The spelling of 120132021031000 in words is "one hundred twenty trillion, one hundred thirty-two billion, twenty-one million, thirty-one thousand".