Base | Representation |
---|---|
bin | 11011010100001001101010… |
… | …011101010010010010111011 |
3 | 120202100111202010012112121020 |
4 | 123110021222131102102323 |
5 | 111221220334430044011 |
6 | 1103255515544113523 |
7 | 34206152323035165 |
oct | 3324115235222273 |
9 | 522314663175536 |
10 | 120132021331131 |
11 | 3530678222a337 |
12 | 11582482a658a3 |
13 | 520552a006b14 |
14 | 21945c6b87935 |
15 | dd4d99b92006 |
hex | 6d426a7524bb |
120132021331131 has 32 divisors (see below), whose sum is σ = 163966243584000. Its totient is φ = 78212149879680.
The previous prime is 120132021331123. The next prime is 120132021331159. The reversal of 120132021331131 is 131133120231021.
It is not a de Polignac number, because 120132021331131 - 23 = 120132021331123 is a prime.
It is a super-2 number, since 2×1201320213311312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120132021331121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 61396410 + ... + 63322848.
It is an arithmetic number, because the mean of its divisors is an integer number (5123945112000).
Almost surely, 2120132021331131 is an apocalyptic number.
120132021331131 is a deficient number, since it is larger than the sum of its proper divisors (43834222252869).
120132021331131 is a wasteful number, since it uses less digits than its factorization.
120132021331131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1928939.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 120132021331131 its reverse (131133120231021), we get a palindrome (251265141562152).
The spelling of 120132021331131 in words is "one hundred twenty trillion, one hundred thirty-two billion, twenty-one million, three hundred thirty-one thousand, one hundred thirty-one".
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