Search a number
-
+
12013202233 is a prime number
BaseRepresentation
bin10110011000000101…
…01110101100111001
31011000012221220102001
423030002232230321
5144100334432413
65304020341001
7603461351134
oct131402565471
934005856361
1012013202233
11510515970a
1223b3244761
131195b07ab6
1481d69721b
154a49cc4dd
hex2cc0aeb39

12013202233 has 2 divisors, whose sum is σ = 12013202234. Its totient is φ = 12013202232.

The previous prime is 12013202221. The next prime is 12013202239. The reversal of 12013202233 is 33220231021.

12013202233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9398720809 + 2614481424 = 96947^2 + 51132^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013202233 - 29 = 12013201721 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12013202233.

It is not a weakly prime, because it can be changed into another prime (12013202239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006601116 + 6006601117.

It is an arithmetic number, because the mean of its divisors is an integer number (6006601117).

Almost surely, 212013202233 is an apocalyptic number.

It is an amenable number.

12013202233 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013202233 is an equidigital number, since it uses as much as digits as its factorization.

12013202233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12013202233 its reverse (33220231021), we get a palindrome (45233433254).

The spelling of 12013202233 in words is "twelve billion, thirteen million, two hundred two thousand, two hundred thirty-three".