Base | Representation |
---|---|
bin | 10001011110110100010… |
… | …101001010011001110111 |
3 | 11020211211011000020011010 |
4 | 101132310111022121313 |
5 | 124140301224301403 |
6 | 2315513541043303 |
7 | 152535601520040 |
oct | 21366425123167 |
9 | 4224734006133 |
10 | 1201321322103 |
11 | 423528627a31 |
12 | 1749a80b6533 |
13 | 89390279ac6 |
14 | 42203bd98c7 |
15 | 213b0bdd603 |
hex | 117b454a677 |
1201321322103 has 32 divisors (see below), whose sum is σ = 1896821194752. Its totient is φ = 661799109600.
The previous prime is 1201321322101. The next prime is 1201321322111. The reversal of 1201321322103 is 3012231231021.
It is not a de Polignac number, because 1201321322103 - 21 = 1201321322101 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 1201321322103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201321322101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3337053 + ... + 3679478.
It is an arithmetic number, because the mean of its divisors is an integer number (59275662336).
Almost surely, 21201321322103 is an apocalyptic number.
1201321322103 is a deficient number, since it is larger than the sum of its proper divisors (695499872649).
1201321322103 is a wasteful number, since it uses less digits than its factorization.
1201321322103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7016835.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1201321322103 its reverse (3012231231021), we get a palindrome (4213552553124).
The spelling of 1201321322103 in words is "one trillion, two hundred one billion, three hundred twenty-one million, three hundred twenty-two thousand, one hundred three".
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