Base | Representation |
---|---|
bin | 1010111011010000101101… |
… | …0100000010101001101111 |
3 | 1120112110012111021211001012 |
4 | 2232310023110002221233 |
5 | 3033311030103030111 |
6 | 41314443301335435 |
7 | 2346632424323414 |
oct | 256641324025157 |
9 | 46473174254035 |
10 | 12013213330031 |
11 | 3911858817271 |
12 | 14202a8a0757b |
13 | 691ac2035074 |
14 | 2d762a7da10b |
15 | 15c757e6148b |
hex | aed0b502a6f |
12013213330031 has 8 divisors (see below), whose sum is σ = 12274343991600. Its totient is φ = 11754489403008.
The previous prime is 12013213329967. The next prime is 12013213330039. The reversal of 12013213330031 is 13003331231021.
12013213330031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12013213330031 - 26 = 12013213329967 is a prime.
It is a super-3 number, since 3×120132133300313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12013213329979 and 12013213330006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013213330039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 601673546 + ... + 601693511.
It is an arithmetic number, because the mean of its divisors is an integer number (1534292998950).
Almost surely, 212013213330031 is an apocalyptic number.
12013213330031 is a deficient number, since it is larger than the sum of its proper divisors (261130661569).
12013213330031 is a wasteful number, since it uses less digits than its factorization.
12013213330031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1203367273.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 12013213330031 its reverse (13003331231021), we get a palindrome (25016544561052).
The spelling of 12013213330031 in words is "twelve trillion, thirteen billion, two hundred thirteen million, three hundred thirty thousand, thirty-one".
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