Search a number
-
+
120132221447 = 717161745921
BaseRepresentation
bin110111111100001110…
…0000011101000000111
3102111002012222011020002
41233320130003220013
53432012322041242
6131104334231515
711451663014450
oct1577034035007
9374065864202
10120132221447
1146a47564047
121b34805559b
13b436700004
145b58b24127
1531d18c2432
hex1bf8703a07

120132221447 has 4 divisors (see below), whose sum is σ = 137293967376. Its totient is φ = 102970475520.

The previous prime is 120132221423. The next prime is 120132221453. The reversal of 120132221447 is 744122231021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120132221447 - 210 = 120132220423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120132221497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8580872954 + ... + 8580872967.

It is an arithmetic number, because the mean of its divisors is an integer number (34323491844).

Almost surely, 2120132221447 is an apocalyptic number.

120132221447 is a deficient number, since it is larger than the sum of its proper divisors (17161745929).

120132221447 is an equidigital number, since it uses as much as digits as its factorization.

120132221447 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17161745928.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 120132221447 its reverse (744122231021), we get a palindrome (864254452468).

The spelling of 120132221447 in words is "one hundred twenty billion, one hundred thirty-two million, two hundred twenty-one thousand, four hundred forty-seven".

Divisors: 1 7 17161745921 120132221447