12013232020222 has 4 divisors (see below), whose sum is σ = 18019848030336. Its totient is φ = 6006616010110.

The previous prime is 12013232020211. The next prime is 12013232020289. The reversal of 12013232020222 is 22202023231021.

It is a semiprime because it is the product of two primes.

It is a super-4 number, since 4×12013232020222⁴ (a number of 53 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013232020193 and 12013232020202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3003308005054 + ... + 3003308005057.

It is an arithmetic number, because the mean of its divisors is an integer number (4504962007584).

Almost surely, 2^{12013232020222} is an apocalyptic number.

12013232020222 is a deficient number, since it is larger than the sum of its proper divisors (6006616010114).

12013232020222 is an equidigital number, since it uses as much as digits as its factorization.

12013232020222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6006616010113.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 12013232020222 its reverse (22202023231021), we get a palindrome (34215255251243).

The spelling of 12013232020222 in words is "twelve trillion, thirteen billion, two hundred thirty-two million, twenty thousand, two hundred twenty-two".