1201323242141 has 4 divisors (see below), whose sum is σ = 1310534445984. Its totient is φ = 1092112038300.

The previous prime is 1201323242123. The next prime is 1201323242179. The reversal of 1201323242141 is 1412423231021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201323242141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1201323242141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201323262141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54605601905 + ... + 54605601926.

It is an arithmetic number, because the mean of its divisors is an integer number (327633611496).

Almost surely, 2^{1201323242141} is an apocalyptic number.

1201323242141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1201323242141 is a deficient number, since it is larger than the sum of its proper divisors (109211203843).

1201323242141 is a wasteful number, since it uses less digits than its factorization.

1201323242141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109211203842.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 1201323242141 its reverse (1412423231021), we get a palindrome (2613746473162).

The spelling of 1201323242141 in words is "one trillion, two hundred one billion, three hundred twenty-three million, two hundred forty-two thousand, one hundred forty-one".