Base | Representation |
---|---|
bin | 1010111011010000110001… |
… | …1111000101011010001011 |
3 | 1120112110020212022021002012 |
4 | 2232310030133011122023 |
5 | 3033311100122031443 |
6 | 41314445243130135 |
7 | 2346633053455433 |
oct | 256641437053213 |
9 | 46473225267065 |
10 | 12013233002123 |
11 | 39118689331a1 |
12 | 14202b351394b |
13 | 691ac6132162 |
14 | 2d762d27b2c3 |
15 | 15c759a4a118 |
hex | aed0c7c568b |
12013233002123 has 2 divisors, whose sum is σ = 12013233002124. Its totient is φ = 12013233002122.
The previous prime is 12013233002081. The next prime is 12013233002137. The reversal of 12013233002123 is 32120033231021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12013233002123 - 228 = 12012964566667 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013233002923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006616501061 + 6006616501062.
It is an arithmetic number, because the mean of its divisors is an integer number (6006616501062).
Almost surely, 212013233002123 is an apocalyptic number.
12013233002123 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013233002123 is an equidigital number, since it uses as much as digits as its factorization.
12013233002123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 12013233002123 its reverse (32120033231021), we get a palindrome (44133266233144).
The spelling of 12013233002123 in words is "twelve trillion, thirteen billion, two hundred thirty-three million, two thousand, one hundred twenty-three".
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