1201324433 has 2 divisors, whose sum is σ = 1201324434. Its totient is φ = 1201324432.

The previous prime is 1201324409. The next prime is 1201324451. The reversal of 1201324433 is 3344231021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 898320784 + 303003649 = 29972^2 + 17407^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201324433 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1201324399 and 1201324408.

It is not a weakly prime, because it can be changed into another prime (1201324133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600662216 + 600662217.

It is an arithmetic number, because the mean of its divisors is an integer number (600662217).

Almost surely, 2^1201324433 is an apocalyptic number.

It is an amenable number.

1201324433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201324433 is an equidigital number, since it uses as much as digits as its factorization.

1201324433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1201324433 is about 34660.1274233088. The cubic root of 1201324433 is about 1063.0493754623.

Adding to 1201324433 its reverse (3344231021), we get a palindrome (4545555454).

The spelling of 1201324433 in words is "one billion, two hundred one million, three hundred twenty-four thousand, four hundred thirty-three".