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120132443314244 = 22179167782742059
BaseRepresentation
bin11011010100001010000011…
…100111000001100001000100
3120202100112211112020111121102
4123110022003213001201010
5111221222220442023434
61103300025500435232
734206165635605514
oct3324120347014104
9522315745214542
10120132443314244
113530697944a509
1211582580248b18
13520559657437a
142194626c31844
15dd4dc1c4907e
hex6d42839c1844

120132443314244 has 12 divisors (see below), whose sum is σ = 211406254995600. Its totient is φ = 59730656172648.

The previous prime is 120132443314181. The next prime is 120132443314321. The reversal of 120132443314244 is 442413344231021.

It is a junction number, because it is equal to n+sod(n) for n = 120132443314198 and 120132443314207.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83891370314 + ... + 83891371745.

It is an arithmetic number, because the mean of its divisors is an integer number (17617187916300).

Almost surely, 2120132443314244 is an apocalyptic number.

It is an amenable number.

120132443314244 is a deficient number, since it is larger than the sum of its proper divisors (91273811681356).

120132443314244 is a wasteful number, since it uses less digits than its factorization.

120132443314244 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167782742242 (or 167782742240 counting only the distinct ones).

The product of its (nonzero) digits is 221184, while the sum is 38.

Adding to 120132443314244 its reverse (442413344231021), we get a palindrome (562545787545265).

The spelling of 120132443314244 in words is "one hundred twenty trillion, one hundred thirty-two billion, four hundred forty-three million, three hundred fourteen thousand, two hundred forty-four".

Divisors: 1 2 4 179 358 716 167782742059 335565484118 671130968236 30033110828561 60066221657122 120132443314244