12013310041234 has 4 divisors (see below), whose sum is σ = 18019965061854. Its totient is φ = 6006655020616.

The previous prime is 12013310041141. The next prime is 12013310041237. The reversal of 12013310041234 is 43214001331021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6304101575209 + 5709208466025 = 2510797^2 + 2389395^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12013310041199 and 12013310041208.

It is not an unprimeable number, because it can be changed into a prime (12013310041237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3003327510307 + ... + 3003327510310.

Almost surely, 2^{12013310041234} is an apocalyptic number.

12013310041234 is a deficient number, since it is larger than the sum of its proper divisors (6006655020620).

12013310041234 is an equidigital number, since it uses as much as digits as its factorization.

12013310041234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6006655020619.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 12013310041234 its reverse (43214001331021), we get a palindrome (55227311372255).

The spelling of 12013310041234 in words is "twelve trillion, thirteen billion, three hundred ten million, forty-one thousand, two hundred thirty-four".