Base | Representation |
---|---|
bin | 110111111100001111… |
… | …1011011001011010111 |
3 | 102111002021122000022221 |
4 | 1233320133123023113 |
5 | 3432013033314333 |
6 | 131104405203211 |
7 | 11452003352500 |
oct | 1577037331327 |
9 | 374067560287 |
10 | 120133104343 |
11 | 46a4800740a |
12 | 1b348400507 |
13 | b43694bb35 |
14 | 5b58cb3ba7 |
15 | 31d19e8d2d |
hex | 1bf87db2d7 |
120133104343 has 12 divisors (see below), whose sum is σ = 139758572232. Its totient is φ = 102962464080.
The previous prime is 120133104307. The next prime is 120133104367. The reversal of 120133104343 is 343401331021.
It is not a de Polignac number, because 120133104343 - 213 = 120133096151 is a prime.
It is a super-2 number, since 2×1201331043432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120133134343) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 513921 + ... + 710197.
It is an arithmetic number, because the mean of its divisors is an integer number (11646547686).
Almost surely, 2120133104343 is an apocalyptic number.
120133104343 is a deficient number, since it is larger than the sum of its proper divisors (19625467889).
120133104343 is a wasteful number, since it uses less digits than its factorization.
120133104343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 208782 (or 208775 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 120133104343 its reverse (343401331021), we get a palindrome (463534435364).
The spelling of 120133104343 in words is "one hundred twenty billion, one hundred thirty-three million, one hundred four thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •