Base | Representation |
---|---|
bin | 10001011110110101000… |
… | …010100011111001101111 |
3 | 11020211211222101212010221 |
4 | 101132311002203321233 |
5 | 124140312301114043 |
6 | 2315515044112211 |
7 | 152536104624433 |
oct | 21366502437157 |
9 | 4224758355127 |
10 | 1201333223023 |
11 | 4235343162aa |
12 | 1749b0095667 |
13 | 8939288597b |
14 | 422056169c3 |
15 | 213b1c8e8ed |
hex | 117b50a3e6f |
1201333223023 has 4 divisors (see below), whose sum is σ = 1202687601840. Its totient is φ = 1199978844208.
The previous prime is 1201333223017. The next prime is 1201333223039. The reversal of 1201333223023 is 3203223331021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201333223023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201333223053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 677188078 + ... + 677189851.
It is an arithmetic number, because the mean of its divisors is an integer number (300671900460).
Almost surely, 21201333223023 is an apocalyptic number.
1201333223023 is a deficient number, since it is larger than the sum of its proper divisors (1354378817).
1201333223023 is an equidigital number, since it uses as much as digits as its factorization.
1201333223023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1354378816.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 1201333223023 its reverse (3203223331021), we get a palindrome (4404556554044).
The spelling of 1201333223023 in words is "one trillion, two hundred one billion, three hundred thirty-three million, two hundred twenty-three thousand, twenty-three".
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