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120133324311 = 371121337227433
BaseRepresentation
bin110111111100010000…
…0010000111000010111
3102111002022001012001220
41233320200100320113
53432013112334221
6131104414021423
711452005260010
oct1577040207027
9374068035056
10120133324311
1146a48147700
121b3484a7873
13b4369c7cb0
145b58d30007
1531d1a3e0c6
hex1bf8810e17

120133324311 has 192 divisors, whose sum is σ = 224046326784. Its totient is φ = 55673671680.

The previous prime is 120133324307. The next prime is 120133324369. The reversal of 120133324311 is 113423331021.

It is not a de Polignac number, because 120133324311 - 22 = 120133324307 is a prime.

It is a super-2 number, since 2×1201333243112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120133324211) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 277443951 + ... + 277444383.

It is an arithmetic number, because the mean of its divisors is an integer number (1166907952).

Almost surely, 2120133324311 is an apocalyptic number.

120133324311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

120133324311 is a deficient number, since it is larger than the sum of its proper divisors (103913002473).

120133324311 is a wasteful number, since it uses less digits than its factorization.

120133324311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 742 (or 731 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 120133324311 its reverse (113423331021), we get a palindrome (233556655332).

It can be divided in two parts, 120133 and 324311, that added together give a palindrome (444444).

The spelling of 120133324311 in words is "one hundred twenty billion, one hundred thirty-three million, three hundred twenty-four thousand, three hundred eleven".