Base | Representation |
---|---|
bin | 10110011000000110… |
… | …11010001001111111 |
3 | 1011000020021221120021 |
4 | 23030003122021333 |
5 | 144100411131343 |
6 | 5304024233011 |
7 | 603463022065 |
oct | 131403321177 |
9 | 34006257507 |
10 | 12013380223 |
11 | 5105270409 |
12 | 23b330b767 |
13 | 1195b6ab10 |
14 | 81d702035 |
15 | 4a4a150ed |
hex | 2cc0da27f |
12013380223 has 4 divisors (see below), whose sum is σ = 12937486408. Its totient is φ = 11089274040.
The previous prime is 12013380221. The next prime is 12013380227. The reversal of 12013380223 is 32208331021.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12013380223 - 21 = 12013380221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013380221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 462053073 + ... + 462053098.
It is an arithmetic number, because the mean of its divisors is an integer number (3234371602).
Almost surely, 212013380223 is an apocalyptic number.
12013380223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12013380223 is a deficient number, since it is larger than the sum of its proper divisors (924106185).
12013380223 is an equidigital number, since it uses as much as digits as its factorization.
12013380223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 924106184.
The product of its (nonzero) digits is 1728, while the sum is 25.
The spelling of 12013380223 in words is "twelve billion, thirteen million, three hundred eighty thousand, two hundred twenty-three".
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