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12013421032153 is a prime number
BaseRepresentation
bin1010111011010001011110…
…1100010111001011011001
31120112110201222010011210101
42232310113230113023121
53033311441241012103
641314520041215401
72346640525630102
oct256642754271331
946473658104711
1012013421032153
113911954a8aa12
121420346491561
13691b26088028
142d764a2253a9
1515c76b2dca1d
hexaed17b172d9

12013421032153 has 2 divisors, whose sum is σ = 12013421032154. Its totient is φ = 12013421032152.

The previous prime is 12013421032097. The next prime is 12013421032199. The reversal of 12013421032153 is 35123012431021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6503096713689 + 5510324318464 = 2550117^2 + 2347408^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013421032153 - 233 = 12004831097561 is a prime.

It is not a weakly prime, because it can be changed into another prime (12013421032453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006710516076 + 6006710516077.

It is an arithmetic number, because the mean of its divisors is an integer number (6006710516077).

Almost surely, 212013421032153 is an apocalyptic number.

It is an amenable number.

12013421032153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013421032153 is an equidigital number, since it uses as much as digits as its factorization.

12013421032153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 12013421032153 its reverse (35123012431021), we get a palindrome (47136433463174).

The spelling of 12013421032153 in words is "twelve trillion, thirteen billion, four hundred twenty-one million, thirty-two thousand, one hundred fifty-three".