12013433030201 has 2 divisors, whose sum is σ = 12013433030202. Its totient is φ = 12013433030200.

The previous prime is 12013433030191. The next prime is 12013433030227. The reversal of 12013433030201 is 10203033431021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10581677196601 + 1431755833600 = 3252949^2 + 1196560^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013433030201 - 2²² = 12013428835897 is a prime.

It is a super-2 number, since 2×12013433030201² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12013433030231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006716515100 + 6006716515101.

It is an arithmetic number, because the mean of its divisors is an integer number (6006716515101).

Almost surely, 2^{12013433030201} is an apocalyptic number.

It is an amenable number.

12013433030201 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013433030201 is an equidigital number, since it uses as much as digits as its factorization.

12013433030201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 12013433030201 its reverse (10203033431021), we get a palindrome (22216466461222).

The spelling of 12013433030201 in words is "twelve trillion, thirteen billion, four hundred thirty-three million, thirty thousand, two hundred one".