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120134412043311 = 371599491940817
BaseRepresentation
bin11011010100001011111000…
…111101001000010000101111
3120202100201220201202022011210
4123110023320331020100233
5111221240233440341221
61103300553105245503
734206265502536431
oct3324137075102057
9522321821668153
10120134412043311
1135307799778826
1211582a2b633893
13520581b3c0103
1421947724aa651
15dd4e899d1276
hex6d42f8f4842f

120134412043311 has 16 divisors (see below), whose sum is σ = 162435704963328. Its totient is φ = 78961369737600.

The previous prime is 120134412043279. The next prime is 120134412043357. The reversal of 120134412043311 is 113340214431021.

It is not a de Polignac number, because 120134412043311 - 25 = 120134412043279 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120134412043391) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 127221175 + ... + 128161991.

It is an arithmetic number, because the mean of its divisors is an integer number (10152231560208).

Almost surely, 2120134412043311 is an apocalyptic number.

120134412043311 is a deficient number, since it is larger than the sum of its proper divisors (42301292920017).

120134412043311 is an equidigital number, since it uses as much as digits as its factorization.

120134412043311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1540382.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 120134412043311 its reverse (113340214431021), we get a palindrome (233474626474332).

The spelling of 120134412043311 in words is "one hundred twenty trillion, one hundred thirty-four billion, four hundred twelve million, forty-three thousand, three hundred eleven".

Divisors: 1 3 71 213 599491 940817 1798473 2822451 42563861 66798007 127691583 200394021 564011324147 1692033972441 40044804014437 120134412043311