Base | Representation |
---|---|
bin | 10110011000000111… |
… | …01001010110010111 |
3 | 1011000020102002221011 |
4 | 23030003221112113 |
5 | 144100420124310 |
6 | 5304025433051 |
7 | 603463401400 |
oct | 131403512627 |
9 | 34006362834 |
10 | 12013442455 |
11 | 5105303143 |
12 | 23b333b787 |
13 | 1195b90241 |
14 | 81d71a9a7 |
15 | 4a4a2878a |
hex | 2cc0e9597 |
12013442455 has 48 divisors (see below), whose sum is σ = 18420065280. Its totient is φ = 7464840768.
The previous prime is 12013442453. The next prime is 12013442477. The reversal of 12013442455 is 55424431021.
12013442455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12013442455 - 21 = 12013442453 is a prime.
It is a super-3 number, since 3×120134424553 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013442453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 50962 + ... + 163168.
It is an arithmetic number, because the mean of its divisors is an integer number (383751360).
Almost surely, 212013442455 is an apocalyptic number.
12013442455 is a deficient number, since it is larger than the sum of its proper divisors (6406622825).
12013442455 is a wasteful number, since it uses less digits than its factorization.
12013442455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112268 (or 112261 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 12013442455 its reverse (55424431021), we get a palindrome (67437873476).
The spelling of 12013442455 in words is "twelve billion, thirteen million, four hundred forty-two thousand, four hundred fifty-five".
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