Base | Representation |
---|---|
bin | 1010111011010001100110… |
… | …0010101010100100010011 |
3 | 1120112110211010110202211011 |
4 | 2232310121202222210103 |
5 | 3033312022210411223 |
6 | 41314523110031351 |
7 | 2346641353343224 |
oct | 256643142524423 |
9 | 46473733422734 |
10 | 12013452044563 |
11 | 3911970542002 |
12 | 1420354948557 |
13 | 691b2c625a78 |
14 | 2d76503b924b |
15 | 15c76ddb680d |
hex | aed198aa913 |
12013452044563 has 2 divisors, whose sum is σ = 12013452044564. Its totient is φ = 12013452044562.
The previous prime is 12013452044527. The next prime is 12013452044579. The reversal of 12013452044563 is 36544025431021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12013452044563 - 233 = 12004862109971 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013452014563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006726022281 + 6006726022282.
It is an arithmetic number, because the mean of its divisors is an integer number (6006726022282).
Almost surely, 212013452044563 is an apocalyptic number.
12013452044563 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013452044563 is an equidigital number, since it uses as much as digits as its factorization.
12013452044563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 12013452044563 its reverse (36544025431021), we get a palindrome (48557477475584).
The spelling of 12013452044563 in words is "twelve trillion, thirteen billion, four hundred fifty-two million, forty-four thousand, five hundred sixty-three".
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