Base | Representation |
---|---|
bin | 10110011000000111… |
… | …11000001111000011 |
3 | 1011000020112012120101 |
4 | 23030003320033003 |
5 | 144100424102202 |
6 | 5304031023231 |
7 | 603464044222 |
oct | 131403701703 |
9 | 34006465511 |
10 | 12013503427 |
11 | 5105344a32 |
12 | 23b336ab17 |
13 | 1195bb1c13 |
14 | 81d734cb9 |
15 | 4a4a3b887 |
hex | 2cc0f83c3 |
12013503427 has 2 divisors, whose sum is σ = 12013503428. Its totient is φ = 12013503426.
The previous prime is 12013503413. The next prime is 12013503449. The reversal of 12013503427 is 72430531021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12013503427 - 227 = 11879285699 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12013503395 and 12013503404.
It is not a weakly prime, because it can be changed into another prime (12013503127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006751713 + 6006751714.
It is an arithmetic number, because the mean of its divisors is an integer number (6006751714).
Almost surely, 212013503427 is an apocalyptic number.
12013503427 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013503427 is an equidigital number, since it uses as much as digits as its factorization.
12013503427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 28.
It can be divided in two parts, 1201 and 3503427, that added together give a triangular number (3504628 = T2647).
The spelling of 12013503427 in words is "twelve billion, thirteen million, five hundred three thousand, four hundred twenty-seven".
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