Base | Representation |
---|---|
bin | 10110011000000111… |
… | …11000001111010101 |
3 | 1011000020112012121001 |
4 | 23030003320033111 |
5 | 144100424102240 |
6 | 5304031023301 |
7 | 603464044246 |
oct | 131403701725 |
9 | 34006465531 |
10 | 12013503445 |
11 | 5105344a49 |
12 | 23b336ab31 |
13 | 1195bb1c28 |
14 | 81d734ccd |
15 | 4a4a3b89a |
hex | 2cc0f83d5 |
12013503445 has 8 divisors (see below), whose sum is σ = 15174951840. Its totient is φ = 9104970960.
The previous prime is 12013503427. The next prime is 12013503449. The reversal of 12013503445 is 54430531021.
12013503445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12013503445 - 25 = 12013503413 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013503449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63228871 + ... + 63229060.
It is an arithmetic number, because the mean of its divisors is an integer number (1896868980).
Almost surely, 212013503445 is an apocalyptic number.
It is an amenable number.
12013503445 is a deficient number, since it is larger than the sum of its proper divisors (3161448395).
12013503445 is a wasteful number, since it uses less digits than its factorization.
12013503445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126457955.
The product of its (nonzero) digits is 7200, while the sum is 28.
The spelling of 12013503445 in words is "twelve billion, thirteen million, five hundred three thousand, four hundred forty-five".
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