Base | Representation |
---|---|
bin | 110111111100010011… |
… | …1000110001010111111 |
3 | 102111002102102012001120 |
4 | 1233320213012022333 |
5 | 3432014042143310 |
6 | 131104520242023 |
7 | 11452026430005 |
oct | 1577047061277 |
9 | 374072365046 |
10 | 120135115455 |
11 | 46a49160393 |
12 | 1b349010313 |
13 | b4371a4344 |
14 | 5b59278a75 |
15 | 31d1c94b70 |
hex | 1bf89c62bf |
120135115455 has 16 divisors (see below), whose sum is σ = 198416707584. Its totient is φ = 62005220640.
The previous prime is 120135115421. The next prime is 120135115469. The reversal of 120135115455 is 554511531021.
It is a happy number.
It is not a de Polignac number, because 120135115455 - 26 = 120135115391 is a prime.
It is a super-4 number, since 4×1201351154554 (a number of 45 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 129177079 + ... + 129178008.
It is an arithmetic number, because the mean of its divisors is an integer number (12401044224).
Almost surely, 2120135115455 is an apocalyptic number.
120135115455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
120135115455 is a deficient number, since it is larger than the sum of its proper divisors (78281592129).
120135115455 is a wasteful number, since it uses less digits than its factorization.
120135115455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258355126.
The product of its (nonzero) digits is 15000, while the sum is 33.
Adding to 120135115455 its reverse (554511531021), we get a palindrome (674646646476).
The spelling of 120135115455 in words is "one hundred twenty billion, one hundred thirty-five million, one hundred fifteen thousand, four hundred fifty-five".
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