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120135794688 = 2143272131279
BaseRepresentation
bin110111111100010100…
…1101100000000000000
3102111002110200200210100
41233320221230000000
53432014230412223
6131104543002400
711452035256200
oct1577051540000
9374073620710
10120135794688
1146a49584738
121b349299400
13b437381560
145b593b4400
1531d1d7b043
hex1bf8a6c000

120135794688 has 540 divisors, whose sum is σ = 435103818240. Its totient is φ = 31659393024.

The previous prime is 120135794629. The next prime is 120135794711. The reversal of 120135794688 is 886497531021.

120135794688 is a `hidden beast` number, since 1 + 2 + 0 + 1 + 3 + 579 + 4 + 68 + 8 = 666.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 93928833 + ... + 93930111.

It is a 2-persistent number, because it is pandigital, and so is 2⋅120135794688 = 240271589376, but 3⋅120135794688 = 360407384064 is not.

Almost surely, 2120135794688 is an apocalyptic number.

120135794688 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120135794688, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217551909120).

120135794688 is an abundant number, since it is smaller than the sum of its proper divisors (314968023552).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120135794688 is a wasteful number, since it uses less digits than its factorization.

120135794688 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1340 (or 1304 counting only the distinct ones).

The product of its (nonzero) digits is 2903040, while the sum is 54.

The spelling of 120135794688 in words is "one hundred twenty billion, one hundred thirty-five million, seven hundred ninety-four thousand, six hundred eighty-eight".