Base | Representation |
---|---|
bin | 1110010100100… |
… | …10100011110011 |
3 | 22101001122022111 |
4 | 13022102203303 |
5 | 221223403341 |
6 | 15530550151 |
7 | 2656104322 |
oct | 712224363 |
9 | 271048274 |
10 | 120137971 |
11 | 618a6488 |
12 | 34298357 |
13 | 1bb74975 |
14 | 11d540b9 |
15 | a831681 |
hex | 72928f3 |
120137971 has 2 divisors, whose sum is σ = 120137972. Its totient is φ = 120137970.
The previous prime is 120137881. The next prime is 120137977. The reversal of 120137971 is 179731021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120137971 - 215 = 120105203 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (120137977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60068985 + 60068986.
It is an arithmetic number, because the mean of its divisors is an integer number (60068986).
Almost surely, 2120137971 is an apocalyptic number.
120137971 is a deficient number, since it is larger than the sum of its proper divisors (1).
120137971 is an equidigital number, since it uses as much as digits as its factorization.
120137971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2646, while the sum is 31.
The square root of 120137971 is about 10960.7468267450. The cubic root of 120137971 is about 493.4313789892.
Adding to 120137971 its reverse (179731021), we get a palindrome (299868992).
The spelling of 120137971 in words is "one hundred twenty million, one hundred thirty-seven thousand, nine hundred seventy-one".
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