Base | Representation |
---|---|
bin | 1010111011010011100100… |
… | …0100100111000110000111 |
3 | 1120112112011222212100221020 |
4 | 2232310321010213012013 |
5 | 3033314113121140220 |
6 | 41315051404122223 |
7 | 2346660435611103 |
oct | 256647104470607 |
9 | 46475158770836 |
10 | 12013981036935 |
11 | 3912112100889 |
12 | 1420481b36373 |
13 | 691bb50bc2c7 |
14 | 2d76a075a903 |
15 | 15c7a055a040 |
hex | aed39127187 |
12013981036935 has 64 divisors (see below), whose sum is σ = 20140854902784. Its totient is φ = 6107532393600.
The previous prime is 12013981036921. The next prime is 12013981037029. The reversal of 12013981036935 is 53963018931021.
12013981036935 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12013981036935 - 212 = 12013981032839 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 394002040 + ... + 394032530.
It is an arithmetic number, because the mean of its divisors is an integer number (314700857856).
Almost surely, 212013981036935 is an apocalyptic number.
12013981036935 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12013981036935 is a deficient number, since it is larger than the sum of its proper divisors (8126873865849).
12013981036935 is a wasteful number, since it uses less digits than its factorization.
12013981036935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43244.
The product of its (nonzero) digits is 1049760, while the sum is 51.
Adding to 12013981036935 its reverse (53963018931021), we get a palindrome (65976999967956).
The spelling of 12013981036935 in words is "twelve trillion, thirteen billion, nine hundred eighty-one million, thirty-six thousand, nine hundred thirty-five".
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