Base | Representation |
---|---|
bin | 1010111011010011101011… |
… | …1000111010011110111011 |
3 | 1120112112021010020022202201 |
4 | 2232310322320322132323 |
5 | 3033314143422300201 |
6 | 41315054413411031 |
7 | 2346661256011534 |
oct | 256647270723673 |
9 | 46475233208681 |
10 | 12014011525051 |
11 | 3912128334a78 |
12 | 1420490199a77 |
13 | 691bbb505503 |
14 | 2d76a481568b |
15 | 15c7a307d801 |
hex | aed3ae3a7bb |
12014011525051 has 2 divisors, whose sum is σ = 12014011525052. Its totient is φ = 12014011525050.
The previous prime is 12014011525037. The next prime is 12014011525073. The reversal of 12014011525051 is 15052511041021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12014011525051 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014011525651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007005762525 + 6007005762526.
It is an arithmetic number, because the mean of its divisors is an integer number (6007005762526).
Almost surely, 212014011525051 is an apocalyptic number.
12014011525051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014011525051 is an equidigital number, since it uses as much as digits as its factorization.
12014011525051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2000, while the sum is 28.
Adding to 12014011525051 its reverse (15052511041021), we get a palindrome (27066522566072).
The spelling of 12014011525051 in words is "twelve trillion, fourteen billion, eleven million, five hundred twenty-five thousand, fifty-one".
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