Base | Representation |
---|---|
bin | 11011010100010010010100… |
… | …111101000111110100101011 |
3 | 120202101101202110022000100212 |
4 | 123110102110331013310223 |
5 | 111221343413002121012 |
6 | 1103304055030051335 |
7 | 34206632004422603 |
oct | 3324222475076453 |
9 | 522341673260325 |
10 | 120141324254507 |
11 | 3530a716511366 |
12 | 1158423a4a9b4b |
13 | 52063804696ca |
14 | 2194c2a4d3c03 |
15 | dd5241758b22 |
hex | 6d4494f47d2b |
120141324254507 has 2 divisors, whose sum is σ = 120141324254508. Its totient is φ = 120141324254506.
The previous prime is 120141324254437. The next prime is 120141324254537. The reversal of 120141324254507 is 705452423141021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120141324254507 - 230 = 120140250512683 is a prime.
It is not a weakly prime, because it can be changed into another prime (120141324254537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60070662127253 + 60070662127254.
It is an arithmetic number, because the mean of its divisors is an integer number (60070662127254).
Almost surely, 2120141324254507 is an apocalyptic number.
120141324254507 is a deficient number, since it is larger than the sum of its proper divisors (1).
120141324254507 is an equidigital number, since it uses as much as digits as its factorization.
120141324254507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 268800, while the sum is 41.
Adding to 120141324254507 its reverse (705452423141021), we get a palindrome (825593747395528).
The spelling of 120141324254507 in words is "one hundred twenty trillion, one hundred forty-one billion, three hundred twenty-four million, two hundred fifty-four thousand, five hundred seven".
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