120143312552561 has 2 divisors, whose sum is σ = 120143312552562. Its totient is φ = 120143312552560.

The previous prime is 120143312552509. The next prime is 120143312552587. The reversal of 120143312552561 is 165255213341021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62326982825536 + 57816329727025 = 7894744^2 + 7603705^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120143312552561 is a prime.

It is a super-2 number, since 2×120143312552561² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120143312552161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60071656276280 + 60071656276281.

It is an arithmetic number, because the mean of its divisors is an integer number (60071656276281).

Almost surely, 2^{120143312552561} is an apocalyptic number.

It is an amenable number.

120143312552561 is a deficient number, since it is larger than the sum of its proper divisors (1).

120143312552561 is an equidigital number, since it uses as much as digits as its factorization.

120143312552561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 41.

Adding to 120143312552561 its reverse (165255213341021), we get a palindrome (285398525893582).

The spelling of 120143312552561 in words is "one hundred twenty trillion, one hundred forty-three billion, three hundred twelve million, five hundred fifty-two thousand, five hundred sixty-one".