Base | Representation |
---|---|
bin | 1010111011010101010010… |
… | …0111010100011000101011 |
3 | 1120112120101012100121222011 |
4 | 2232311110213110120223 |
5 | 3033321034414321141 |
6 | 41315205312140351 |
7 | 2350005046344412 |
oct | 256652447243053 |
9 | 46476335317864 |
10 | 12014443120171 |
11 | 3912329a1a858 |
12 | 14205908376b7 |
13 | 691c59a59b3b |
14 | 2d7705c82479 |
15 | 15c7cadd3881 |
hex | aed549d462b |
12014443120171 has 2 divisors, whose sum is σ = 12014443120172. Its totient is φ = 12014443120170.
The previous prime is 12014443120129. The next prime is 12014443120223. The reversal of 12014443120171 is 17102134441021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12014443120171 - 215 = 12014443087403 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014443120271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007221560085 + 6007221560086.
It is an arithmetic number, because the mean of its divisors is an integer number (6007221560086).
Almost surely, 212014443120171 is an apocalyptic number.
12014443120171 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014443120171 is an equidigital number, since it uses as much as digits as its factorization.
12014443120171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 31.
Adding to 12014443120171 its reverse (17102134441021), we get a palindrome (29116577561192).
The spelling of 12014443120171 in words is "twelve trillion, fourteen billion, four hundred forty-three million, one hundred twenty thousand, one hundred seventy-one".
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