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120145031561 is a prime number
BaseRepresentation
bin110111111100100110…
…0111011000110001001
3102111010010001222101202
41233321030323012021
53432024112002221
6131105512553545
711452206626642
oct1577114730611
9374103058352
10120145031561
1146a53813515
121b3503b28b5
13b439266969
145b5a6da6c9
1531d2aa2d0b
hex1bf933b189

120145031561 has 2 divisors, whose sum is σ = 120145031562. Its totient is φ = 120145031560.

The previous prime is 120145031459. The next prime is 120145031569. The reversal of 120145031561 is 165130541021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65667137536 + 54477894025 = 256256^2 + 233405^2 .

It is an emirp because it is prime and its reverse (165130541021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120145031561 - 230 = 119071289737 is a prime.

It is not a weakly prime, because it can be changed into another prime (120145031569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60072515780 + 60072515781.

It is an arithmetic number, because the mean of its divisors is an integer number (60072515781).

Almost surely, 2120145031561 is an apocalyptic number.

It is an amenable number.

120145031561 is a deficient number, since it is larger than the sum of its proper divisors (1).

120145031561 is an equidigital number, since it uses as much as digits as its factorization.

120145031561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 120145031561 its reverse (165130541021), we get a palindrome (285275572582).

The spelling of 120145031561 in words is "one hundred twenty billion, one hundred forty-five million, thirty-one thousand, five hundred sixty-one".