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12015132351 = 34005044117
BaseRepresentation
bin10110011000010100…
…00101111010111111
31011000100120222000220
423030022011322333
5144101333213401
65304125552423
7603513640245
oct131412057277
934010528026
1012015132351
115106257852
1223b3a15713
131196332491
1481da3a795
154a4c5e336
hex2cc285ebf

12015132351 has 4 divisors (see below), whose sum is σ = 16020176472. Its totient is φ = 8010088232.

The previous prime is 12015132319. The next prime is 12015132377. The reversal of 12015132351 is 15323151021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12015132351 - 25 = 12015132319 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12015131351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002522056 + ... + 2002522061.

It is an arithmetic number, because the mean of its divisors is an integer number (4005044118).

Almost surely, 212015132351 is an apocalyptic number.

12015132351 is a deficient number, since it is larger than the sum of its proper divisors (4005044121).

12015132351 is an equidigital number, since it uses as much as digits as its factorization.

12015132351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4005044120.

The product of its (nonzero) digits is 900, while the sum is 24.

Adding to 12015132351 its reverse (15323151021), we get a palindrome (27338283372).

The spelling of 12015132351 in words is "twelve billion, fifteen million, one hundred thirty-two thousand, three hundred fifty-one".

Divisors: 1 3 4005044117 12015132351