Base | Representation |
---|---|
bin | 110111111101001000… |
… | …1100100010000111111 |
3 | 102111011100221012002211 |
4 | 1233322101210100333 |
5 | 3432043213312413 |
6 | 131111354401251 |
7 | 11452515603550 |
oct | 1577221442077 |
9 | 374140835084 |
10 | 120163025983 |
11 | 46a62993a40 |
12 | 1b356430227 |
13 | b43cbc7250 |
14 | 5b5cc62327 |
15 | 31d445983d |
hex | 1bfa46443f |
120163025983 has 32 divisors (see below), whose sum is σ = 163281710592. Its totient is φ = 85389552000.
The previous prime is 120163025929. The next prime is 120163026001. The reversal of 120163025983 is 389520361021.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120163025983 is a prime.
It is a super-2 number, since 2×1201630259832 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120163025183) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 640068 + ... + 806233.
It is an arithmetic number, because the mean of its divisors is an integer number (5102553456).
Almost surely, 2120163025983 is an apocalyptic number.
120163025983 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120163025983 is a deficient number, since it is larger than the sum of its proper divisors (43118684609).
120163025983 is a wasteful number, since it uses less digits than its factorization.
120163025983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1446415.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 120163025983 in words is "one hundred twenty billion, one hundred sixty-three million, twenty-five thousand, nine hundred eighty-three".
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