Base | Representation |
---|---|
bin | 1010111011011111100100… |
… | …0101001100011110110010 |
3 | 1120112211111111110100121212 |
4 | 2232313321011030132302 |
5 | 3033342212304244123 |
6 | 41320343201320122 |
7 | 2350133323101335 |
oct | 256677105143662 |
9 | 46484444410555 |
10 | 12017202415538 |
11 | 3913515526251 |
12 | 1421020936042 |
13 | 6922a96048a8 |
14 | 2d78c850c61c |
15 | 15c8dd27c878 |
hex | aedf914c7b2 |
12017202415538 has 16 divisors (see below), whose sum is σ = 18720998610840. Its totient is φ = 5780518862976.
The previous prime is 12017202415523. The next prime is 12017202415541. The reversal of 12017202415538 is 83551420271021.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 11996919813649 + 20282601889 = 3463657^2 + 142417^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12017202415495 and 12017202415504.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 912322781 + ... + 912335952.
Almost surely, 212017202415538 is an apocalyptic number.
12017202415538 is a deficient number, since it is larger than the sum of its proper divisors (6703796195302).
12017202415538 is a wasteful number, since it uses less digits than its factorization.
12017202415538 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1824658861.
The product of its (nonzero) digits is 134400, while the sum is 41.
Adding to 12017202415538 its reverse (83551420271021), we get a palindrome (95568622686559).
The spelling of 12017202415538 in words is "twelve trillion, seventeen billion, two hundred two million, four hundred fifteen thousand, five hundred thirty-eight".
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