12018018362171 has 2 divisors, whose sum is σ = 12018018362172. Its totient is φ = 12018018362170.

The previous prime is 12018018362153. The next prime is 12018018362333. The reversal of 12018018362171 is 17126381081021.

It is a weak prime.

It is an emirp because it is prime and its reverse (17126381081021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12018018362171 - 2¹⁴ = 12018018345787 is a prime.

It is a super-3 number, since 3×12018018362171³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12018018367171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6009009181085 + 6009009181086.

It is an arithmetic number, because the mean of its divisors is an integer number (6009009181086).

Almost surely, 2^{12018018362171} is an apocalyptic number.

12018018362171 is a deficient number, since it is larger than the sum of its proper divisors (1).

12018018362171 is an equidigital number, since it uses as much as digits as its factorization.

12018018362171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 41.

The spelling of 12018018362171 in words is "twelve trillion, eighteen billion, eighteen million, three hundred sixty-two thousand, one hundred seventy-one".