Base | Representation |
---|---|
bin | 11011010101001010000101… |
… | …111100100110010011011001 |
3 | 120202121010022102211200222121 |
4 | 123111022011330212103121 |
5 | 111223334030203013423 |
6 | 1103351400410021241 |
7 | 34214151561032452 |
oct | 3325120574462331 |
9 | 522533272750877 |
10 | 120201202001113 |
11 | 35333052988662 |
12 | 1159396b417821 |
13 | 520bc037910bc |
14 | 2197aaaa42129 |
15 | dd6a983ad45d |
hex | 6d5285f264d9 |
120201202001113 has 2 divisors, whose sum is σ = 120201202001114. Its totient is φ = 120201202001112.
The previous prime is 120201202000951. The next prime is 120201202001117. The reversal of 120201202001113 is 311100202102021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62396855092224 + 57804346908889 = 7899168^2 + 7602917^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120201202001113 is a prime.
It is not a weakly prime, because it can be changed into another prime (120201202001117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60100601000556 + 60100601000557.
It is an arithmetic number, because the mean of its divisors is an integer number (60100601000557).
Almost surely, 2120201202001113 is an apocalyptic number.
It is an amenable number.
120201202001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
120201202001113 is an equidigital number, since it uses as much as digits as its factorization.
120201202001113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 120201202001113 its reverse (311100202102021), we get a palindrome (431301404103134).
The spelling of 120201202001113 in words is "one hundred twenty trillion, two hundred one billion, two hundred two million, one thousand, one hundred thirteen".
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