Base | Representation |
---|---|
bin | 10001011111011110100… |
… | …101000000110010110001 |
3 | 11020220122112201220020021 |
4 | 101133132211000302301 |
5 | 124143224202320423 |
6 | 2320112141043441 |
7 | 152562266303404 |
oct | 21373645006261 |
9 | 4226575656207 |
10 | 1202030120113 |
11 | 423861736409 |
12 | 174b65556581 |
13 | 89474079904 |
14 | 4226ddc3d3b |
15 | 2140304c95d |
hex | 117de940cb1 |
1202030120113 has 2 divisors, whose sum is σ = 1202030120114. Its totient is φ = 1202030120112.
The previous prime is 1202030120089. The next prime is 1202030120119. The reversal of 1202030120113 is 3110210302021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1047885937569 + 154144182544 = 1023663^2 + 392612^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202030120113 - 213 = 1202030111921 is a prime.
It is not a weakly prime, because it can be changed into another prime (1202030120119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601015060056 + 601015060057.
It is an arithmetic number, because the mean of its divisors is an integer number (601015060057).
Almost surely, 21202030120113 is an apocalyptic number.
It is an amenable number.
1202030120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202030120113 is an equidigital number, since it uses as much as digits as its factorization.
1202030120113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1202030120113 its reverse (3110210302021), we get a palindrome (4312240422134).
The spelling of 1202030120113 in words is "one trillion, two hundred two billion, thirty million, one hundred twenty thousand, one hundred thirteen".
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