Base | Representation |
---|---|
bin | 1010111011101011001110… |
… | …1011111011000111110111 |
3 | 1120120010120200110010210220 |
4 | 2232322303223323013313 |
5 | 3033420120240131411 |
6 | 41322021555345423 |
7 | 2350304026532406 |
oct | 256726353730767 |
9 | 46503520403726 |
10 | 12020333130231 |
11 | 3914881756568 |
12 | 14217552b2273 |
13 | 6926880c4caa |
14 | 2d7b0421d63d |
15 | 15ca23041b06 |
hex | aeeb3afb1f7 |
12020333130231 has 16 divisors (see below), whose sum is σ = 16035277943808. Its totient is φ = 8009472643200.
The previous prime is 12020333130203. The next prime is 12020333130241. The reversal of 12020333130231 is 13203133302021.
It is not a de Polignac number, because 12020333130231 - 26 = 12020333130167 is a prime.
It is a super-2 number, since 2×120203331302312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12020333130241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65722671 + ... + 65905311.
It is an arithmetic number, because the mean of its divisors is an integer number (1002204871488).
Almost surely, 212020333130231 is an apocalyptic number.
12020333130231 is a deficient number, since it is larger than the sum of its proper divisors (4014944813577).
12020333130231 is a wasteful number, since it uses less digits than its factorization.
12020333130231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193702.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 12020333130231 its reverse (13203133302021), we get a palindrome (25223466432252).
The spelling of 12020333130231 in words is "twelve trillion, twenty billion, three hundred thirty-three million, one hundred thirty thousand, two hundred thirty-one".
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