Base | Representation |
---|---|
bin | 110111111110010111… |
… | …1011100100111110111 |
3 | 102111021020210220000021 |
4 | 1233330233130213313 |
5 | 3432134312212211 |
6 | 131115433430011 |
7 | 11453530440634 |
oct | 1577457344767 |
9 | 374236726007 |
10 | 120204413431 |
11 | 46a84291a43 |
12 | 1b36826b307 |
13 | b44865846b |
14 | 5b6455718b |
15 | 31d7dd2771 |
hex | 1bfcbdc9f7 |
120204413431 has 12 divisors (see below), whose sum is σ = 121585372272. Its totient is φ = 118838572448.
The previous prime is 120204413377. The next prime is 120204413479. The reversal of 120204413431 is 134314402021.
It is not a de Polignac number, because 120204413431 - 29 = 120204412919 is a prime.
It is a super-2 number, since 2×1202044134312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120204413396 and 120204413405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120204413491) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5748411 + ... + 5769283.
It is an arithmetic number, because the mean of its divisors is an integer number (10132114356).
Almost surely, 2120204413431 is an apocalyptic number.
120204413431 is a deficient number, since it is larger than the sum of its proper divisors (1380958841).
120204413431 is an equidigital number, since it uses as much as digits as its factorization.
120204413431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21590 (or 21483 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 120204413431 its reverse (134314402021), we get a palindrome (254518815452).
The spelling of 120204413431 in words is "one hundred twenty billion, two hundred four million, four hundred thirteen thousand, four hundred thirty-one".
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