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120211030121131 is a prime number
BaseRepresentation
bin11011010101010011001111…
…101111111001101010101011
3120202122001200101011221002201
4123111103033233321222223
5111224014142202334011
61103400103532441031
734214650250465545
oct3325231757715253
9522561611157081
10120211030121131
11353372366766a4
1211595852919177
13520cb0b98b631
142198360022695
15dd6e71118cc1
hex6d54cfbf9aab

120211030121131 has 2 divisors, whose sum is σ = 120211030121132. Its totient is φ = 120211030121130.

The previous prime is 120211030121101. The next prime is 120211030121233. The reversal of 120211030121131 is 131121030112021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120211030121131 - 243 = 111414937098923 is a prime.

It is a super-2 number, since 2×1202110301211312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120211030121099 and 120211030121108.

It is not a weakly prime, because it can be changed into another prime (120211030121101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105515060565 + 60105515060566.

It is an arithmetic number, because the mean of its divisors is an integer number (60105515060566).

Almost surely, 2120211030121131 is an apocalyptic number.

120211030121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

120211030121131 is an equidigital number, since it uses as much as digits as its factorization.

120211030121131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 120211030121131 its reverse (131121030112021), we get a palindrome (251332060233152).

The spelling of 120211030121131 in words is "one hundred twenty trillion, two hundred eleven billion, thirty million, one hundred twenty-one thousand, one hundred thirty-one".