120211214443130 has 16 divisors (see below), whose sum is σ = 216384936476040. Its totient is φ = 48083430115392.

The previous prime is 120211214443081. The next prime is 120211214443163. The reversal of 120211214443130 is 31344412112021.

It can be written as a sum of positive squares in 4 ways, for example, as 74686601063881 + 45524613379249 = 8642141^2 + 6747193^2 .

It is a junction number, because it is equal to n+sod(n) for n = 120211214443093 and 120211214443102.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 131479385 + ... + 132390524.

Almost surely, 2^{120211214443130} is an apocalyptic number.

120211214443130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

120211214443130 is a deficient number, since it is larger than the sum of its proper divisors (96173722032910).

120211214443130 is a wasteful number, since it uses less digits than its factorization.

120211214443130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 263915473.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 120211214443130 its reverse (31344412112021), we get a palindrome (151555626555151).

The spelling of 120211214443130 in words is "one hundred twenty trillion, two hundred eleven billion, two hundred fourteen million, four hundred forty-three thousand, one hundred thirty".