Base | Representation |
---|---|
bin | 110111111110100100… |
… | …1110010111000001011 |
3 | 102111021201210210111101 |
4 | 1233331021302320023 |
5 | 3432143044222311 |
6 | 131120241442231 |
7 | 11453643235444 |
oct | 1577511627013 |
9 | 374251723441 |
10 | 120211320331 |
11 | 46a8817a223 |
12 | 1b36a640377 |
13 | b449c0619b |
14 | 5b654342cb |
15 | 31d87e8ec1 |
hex | 1bfd272e0b |
120211320331 has 2 divisors, whose sum is σ = 120211320332. Its totient is φ = 120211320330.
The previous prime is 120211320301. The next prime is 120211320353. The reversal of 120211320331 is 133023112021.
It is a strong prime.
It is an emirp because it is prime and its reverse (133023112021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120211320331 - 213 = 120211312139 is a prime.
It is a super-2 number, since 2×1202113203312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120211320299 and 120211320308.
It is not a weakly prime, because it can be changed into another prime (120211320301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105660165 + 60105660166.
It is an arithmetic number, because the mean of its divisors is an integer number (60105660166).
Almost surely, 2120211320331 is an apocalyptic number.
120211320331 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211320331 is an equidigital number, since it uses as much as digits as its factorization.
120211320331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 120211320331 its reverse (133023112021), we get a palindrome (253234432352).
The spelling of 120211320331 in words is "one hundred twenty billion, two hundred eleven million, three hundred twenty thousand, three hundred thirty-one".
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