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1202114342323 is a prime number
BaseRepresentation
bin10001011111100011100…
…110010010110110110011
311020220212102012211101101
4101133203212102312303
5124143412232423243
62320124350145231
7152564341213246
oct21374346226663
94226772184341
101202114342323
114238a5230844
12174b897b2217
1389488657a3b
144227b26925d
152140a63754d
hex117e3992db3

1202114342323 has 2 divisors, whose sum is σ = 1202114342324. Its totient is φ = 1202114342322.

The previous prime is 1202114342311. The next prime is 1202114342381. The reversal of 1202114342323 is 3232434112021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1202114342323 - 213 = 1202114334131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1202114342291 and 1202114342300.

It is not a weakly prime, because it can be changed into another prime (1202114342383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601057171161 + 601057171162.

It is an arithmetic number, because the mean of its divisors is an integer number (601057171162).

Almost surely, 21202114342323 is an apocalyptic number.

1202114342323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202114342323 is an equidigital number, since it uses as much as digits as its factorization.

1202114342323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1202114342323 its reverse (3232434112021), we get a palindrome (4434548454344).

The spelling of 1202114342323 in words is "one trillion, two hundred two billion, one hundred fourteen million, three hundred forty-two thousand, three hundred twenty-three".